Bait weight

[Drew03cmc]

Does anyone have or know the weight of a Rapala SSR05 without split rings and hooks?

[IndianaOutdoors]

I might have one at home. And I might have a scale too.  I'll see if I can get a weight for you when I get home.  Why do you want to know?

[Drew03cmc]

I was just in the yard tossing it around on my Morrum 1600 and original model 5'6" Lightning Rod. I know the bait is 3/16 as sold.

[IndianaOutdoors]

Sorry man can't find my scale. I think my buddy has it.

[rippin-lips]

Subtract roughly 2 grams since it has #8 hooks. 

[Drew03cmc]

2 grams from 3/16? Oh Lord, quit making me think.

[islandbass]

Lol.  I haven't done such math in a VERY long time, but I had math teachers that drilled concepts in my head that have been burned into memory but I can easily forget my cell phone or wallet at home on the way to work, lol.

 

With ounces and grams we are dealing with US and Metric units.  Unfortunately, sometimes conversions are "icky" because and this is the case here.  

 

This is the deal - 1 lb = 16 oz = 453.6 grams   for the sake of simplicity, we will round that to 454 gr.

 

If the Rapala lure weighs 3/16 oz with the trebles and the two trebles weight about 2 grams, most engineers and physicists will tell you that that is such a small amount of weight is practically negligible to warrant the trouble to calculate.  However, the mathematician would disagree and actually salivate at the prospect of proceed with such a fun exercise of the brain.

 

First things first.  The easiest way to proceed is to get/convert the values at hand into the same units. Since we Americans are not accustomed to using metric units as the rest of the world, let's stick with ounces.  A simple ratio and basic algebra will get us there.

 

Let w be the weight in ounces of 2 grams

 

16 oz  = 454 gr           Now that we have set up the appropriate ratio, we can solve for w.

   w           2 gr

 

We do this by isolating the variable w from the other terms.  Remember cross multiplication, lol?

 

16 oz (2 gr) = 454 gr (w)              We can now solve for w by dividing both sides of the equation by 454 gr

 

The equation will now look like this

 

16 oz (2 gr) = w           The "gr" terms in the numerator and denominator of the term on the left cancel each other

   454 gr

 

  32 oz  = w      This leaves us with simple division for which the quotient is 0.07048 oz 

   454

 

Therefore, 2 grams is 0.07048 oz.

 

3/16 oz in decimal form = 0.1875 as every 4th grader should have ingrained in their minds, lol.

 

0.1875 - 0.07048 = 0.11702 oz    This is the true weight.

 

That is going to make for an ugly calculation to convert back into a fraction.  The engineer and physicist are laughing because they already knew the difference was negligible. 0.07 (yes, I truncated last three digits, lol) is 7/100 and this is a small figure.

 

If  you did want to convert that into a fraction, you'd have to start with 0.11702/1 and multiply the numerator and denominator by 100,000 to get rid of the decimal.  The rest as they say, is elementary, lol.

 

 

 

 

[Drew03cmc]

The bait is just under 1/8oz. Got it. Thanks for the math lesson. I'm off for the Advil.

[fishwizzard]

I cheat and printed out a fractional ounce to decimal ounce chart and hung it over my little fishing workbench.  

 

Buying a little scale was one of the best tackle investments I have ever made.  Nothing weighs what the package says, rods don't seem to have accurate weight ratings, so the only way to really tell is to test stuff in the yard and weigh stuff on the bench.  

[TOXIC]

You would be shocked if you weighed 1/4 oz jigheads for example and found out how many are actually 1/4 oz.  

[J Francho]

I leave the math at home, and simply use time on the water, actually fishing the baits to see what works with what, and when.

[fishwizzard]

1 hour ago, J Francho said:

I leave the math at home, and simply use time on the water, actually fishing the baits to see what works with what, and when.

That gets heavy if you are fishing on foot.  

 

What got me to buy the scale was getting into jigs/chatterbaits.  A "3/8oz" chatterbait, once you account for the skirt and blade, often weighs a bit north of 1/2oz.  Throw on a trailer and you are north of 3/4oz.  Trying to fish that on a rod with a printed max of 3/4oz, who's real upper limit feels closer to 1/2oz, was incredibly frustrating.  Knowing what my lures really weigh and learning what my rods really cast best with is something I would rather do in my yard with a beer next to me then 3 miles from my car in the woods.  

[J Francho]

I think you're over complicating things, but if it's what you enjoy, have it it.

[fishwizzard]

3 minutes ago, J Francho said:

I think you're over complicating things, but if it's what you enjoy, have it it.

That is likely, but I did end up with a pile of chatterbaits that were too heavy for my rod.  I mean, I did the sensible thing and bought a heavier rod to throw them on, but still.  

[J Francho]

I get it.  I toil with setups for hours the night before a trip.  There's usually a beverage involved, lol.

[islandbass]

2 hours ago, J Francho said:

I leave the math at home, and simply use time on the water, actually fishing the baits to see what works with what, and when.

 

I agree with you 100%, but it was after midnight and I was taking a break from writing music (rather be fishing) and had nothing better to do, lol. 

 

I had passionate math teachers in my elementary and middle school years who did an excellent job such that nearly 40 years later, I don't know how I still remember what they taught, but at times I can't remember where I put my keys. Long term and short term memory are two different animals. 

[Jaderose]

On 9/12/2017 at 2:47 AM, islandbass said:

Lol.  I haven't done such math in a VERY long time, but I had math teachers that drilled concepts in my head that have been burned into memory but I can easily forget my cell phone or wallet at home on the way to work, lol.

 

With ounces and grams we are dealing with US and Metric units.  Unfortunately, sometimes conversions are "icky" because and this is the case here.  

 

This is the deal - 1 lb = 16 oz = 453.6 grams   for the sake of simplicity, we will round that to 454 gr.

 

If the Rapala lure weighs 3/16 oz with the trebles and the two trebles weight about 2 grams, most engineers and physicists will tell you that that is such a small amount of weight is practically negligible to warrant the trouble to calculate.  However, the mathematician would disagree and actually salivate at the prospect of proceed with such a fun exercise of the brain.

 

First things first.  The easiest way to proceed is to get/convert the values at hand into the same units. Since we Americans are not accustomed to using metric units as the rest of the world, let's stick with ounces.  A simple ratio and basic algebra will get us there.

 

Let w be the weight in ounces of 2 grams

 

16 oz  = 454 gr           Now that we have set up the appropriate ratio, we can solve for w.

   w           2 gr

 

We do this by isolating the variable w from the other terms.  Remember cross multiplication, lol?

 

16 oz (2 gr) = 454 gr (w)              We can now solve for w by dividing both sides of the equation by 454 gr

 

The equation will now look like this

 

16 oz (2 gr) = w           The "gr" terms in the numerator and denominator of the term on the left cancel each other

   454 gr

 

  32 oz  = w      This leaves us with simple division for which the quotient is 0.07048 oz 

   454

 

Therefore, 2 grams is 0.07048 oz.

 

3/16 oz in decimal form = 0.1875 as every 4th grader should have ingrained in their minds, lol.

 

0.1875 - 0.07048 = 0.11702 oz    This is the true weight.

 

That is going to make for an ugly calculation to convert back into a fraction.  The engineer and physicist are laughing because they already knew the difference was negligible. 0.07 (yes, I truncated last three digits, lol) is 7/100 and this is a small figure.

 

If  you did want to convert that into a fraction, you'd have to start with 0.11702/1 and multiply the numerator and denominator by 100,000 to get rid of the decimal.  The rest as they say, is elementary, lol.