TRYTOFISH Posted November 16, 2012 Posted November 16, 2012 got a new boat that has a fortrex with tranducer in trolling mtr. it is a dual beam trans ducer. i know the rule of thumb is on a 20 degree cone is 1/3 depth. 10' = 3.3' of bottom. is there a rule of thumb for a 60 degree angle? is it x 3? 10' = 9.9' of bottom. i have fancy stuff but a generic brain. hoping i can catch up someday. Quote
Super User J Francho Posted November 16, 2012 Super User Posted November 16, 2012 It's a little more than the depth. Quote
Super User Wayne P. Posted November 16, 2012 Super User Posted November 16, 2012 60 degrees is about 1 1/2 times the depth at the spec -10db strength. The actual coverage of 83 kHz is a lot more at lesser strengths. That applies to the 200 kHz 20 degree coverage that is about 1/3 of the depth at -10 db. I'll post a coverage chart later for both cone angles. I have to get those loaded to Photobucket. Quote
TRYTOFISH Posted November 16, 2012 Author Posted November 16, 2012 thats what i am asking. is it frequency or what? where can i go to find out? Quote
TRYTOFISH Posted November 16, 2012 Author Posted November 16, 2012 60 degrees is about 1 1/2 times the depth at the spec -10db strength. The actual coverage of 83 kHz is a lot more at lesser strengths. That applies to the 200 kHz 20 degree coverage that is about 1/3 of the depth at -10 db. I'll post a coverage chart later for both cone angles. I have to get those loaded to Photobucket. thanks! like i said before. simple minds need simple solutions. Quote
moguy1973 Posted November 16, 2012 Posted November 16, 2012 60 degree cone covers about 11.5' of the bottom at 10 feet of depth. The formula is tan(1/2 angle of cone) x depth = bottom then multiply by two. Easy to figure out with a scientific calculator. For example. For 10' depth and a 20* cone Tan(20/2) x 10' = 1.76 x 2 = 3.52' bottom coverage For 10' depth and a 60* cone Tan(60/2) x 10' = 5.77 x 2 = 11.54' Quote
TRYTOFISH Posted November 17, 2012 Author Posted November 17, 2012 thanks for the info fellas. help me out alot. i appreciate you taking the time to help. its nice to have a place to go to get honest answers and opinions. do not do alot of internet stuff, but this website is the best ive found for friendly and informed people. once again, thanks 1 Quote
moguy1973 Posted November 17, 2012 Posted November 17, 2012 Oops, my graph didn't copy over like it should have... Wayne, your calculations are a little off, esp on the 60 degree cone... Quote
Super User Wayne P. Posted November 17, 2012 Super User Posted November 17, 2012 They are not my calculations. Quote
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